Square Roots — Perfect Squares & Non-Perfect Approximation
Find square roots of perfect squares instantly using the last-digit method, squares ending in 5 shortcut, and approximate non-perfect square roots using the nearest perfect square formula
Square Roots — Perfect & Non-Perfect Numbers
Last Digit of Squares
The last digit of a number's square depends only on its last digit:
| Last digit | Square ends with |
|---|---|
| 0 | 0 |
| 1 | 1 |
| 2 | 4 |
| 3 | 9 |
| 4 | 6 |
| 5 | 5 |
| 6 | 6 |
| 7 | 9 |
| 8 | 4 |
| 9 | 1 |
Key pairs: 2↔8 (both end in 4), 3↔7 (both end in 9), 4↔6 (both end in 6), 1↔9 (both end in 1), 5→5, 0→0
Finding Square Roots of Perfect Squares (2-Step Method)
Step 1: Identify the range
Find the nearest multiples of 5 or 10 whose squares bracket the number.
Step 2: Use last digit to pick the exact answer
From the last digit of the number, determine which digit the root ends with.
Example 1: √2116
- Range: 45² = 2025, 50² = 2500 → root is between 45 and 50
- Last digit of 2116 is 6 → root ends in 4 or 6
- Between 45-50: only 46 ends in 6
- √2116 = 46 ✓
Example 2: √5329
- 70² = 4900, 75² = 5625 → root is between 70 and 75
- Last digit is 9 → root ends in 3 or 7
- 73² ends in 9 ✓ → √5329 = 73
Example 3: √4489
- 65² = 4225, 70² = 4900 → between 65 and 70
- Last digit 9 → ends in 3 or 7
- 67² ends in 9 ✓ → √4489 = 67
Example 4: √7396
- 85² = 7225, 90² = 8100 → between 85 and 90
- Last digit 6 → ends in 4 or 6
- 86² → √7396 = 86
Example 5: √8464
- 90² = 8100, 95² = 9025 → between 90 and 95
- Last digit 4 → ends in 2 or 8
- 92² → √8464 = 92
Example 6: √3481
- 55² = 3025, 60² = 3600 → between 55 and 60
- Last digit 1 → ends in 1 or 9
- 59² → √3481 = 59
Example 7: √2916
- 50² = 2500, 55² = 3025 → between 50 and 55
- Last digit 6 → ends in 4 or 6
- 54² → √2916 = 54
Example 8: √6084
- 75² = 5625, 80² = 6400 → between 75 and 80
- Last digit 4 → ends in 2 or 8
- 78² → √6084 = 78
Squaring Numbers Ending in 5 (Instant Shortcut)
For any number ending in 5: n5² = n(n+1) | 25
Write n × (n+1) followed by 25.
| Number | n × (n+1) | Result |
|---|---|---|
| 15² | 1 × 2 = 2 | 225 |
| 25² | 2 × 3 = 6 | 625 |
| 35² | 3 × 4 = 12 | 1225 |
| 45² | 4 × 5 = 20 | 2025 |
| 55² | 5 × 6 = 30 | 3025 |
| 65² | 6 × 7 = 42 | 4225 |
| 75² | 7 × 8 = 56 | 5625 |
| 85² | 8 × 9 = 72 | 7225 |
| 95² | 9 × 10 = 90 | 9025 |
This shortcut makes finding ranges for square roots much faster — you instantly know the "bookend" perfect squares.
Square Roots of Non-Perfect Numbers (Approximation)
The Formula:
√(a ± b) ≈ √a ± b/(2√a)
Where a is the nearest perfect square and b is the difference.
Example 1: √210
- Nearest perfect square: 196 (= 14²). Extra: 210 − 196 = 14
- √210 = √196 + 14/(2×14) = 14 + 14/28 = 14 + 0.5 = 14.5
Example 2: √264
- Nearest: 256 (= 16²). Extra: 264 − 256 = 8
- √264 = 16 + 8/(2×16) = 16 + 8/32 = 16 + 0.25 = 16.25
Example 3: √568
- Nearest: 576 (= 24²). Deficit: 576 − 568 = 8
- √568 = 24 − 8/(2×24) = 24 − 8/48 = 24 − 0.166 = 23.83
Example 4: √717
- Nearest: 729 (= 27²). Deficit: 729 − 717 = 12
- √717 = 27 − 12/(2×27) = 27 − 12/54 = 27 − 0.222 = 26.78
When to use: This approximation is accurate enough for exam-level simplification and DI questions where exact values aren't needed.
Practice Problems
| # | Problem | Answer |
|---|---|---|
| 1 | √3481 | 59 |
| 2 | √6084 | 78 |
| 3 | √8464 | 92 |
| 4 | 55² (instant) | 3025 |
| 5 | 85² (instant) | 7225 |
| 6 | √210 (approx) | ≈ 14.5 |
| 7 | √568 (approx) | ≈ 23.83 |
| 8 | √7396 | 86 |
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